Q:

Ip Subnet Mask, network Devision

I' ve been trying all day to find out how to devide a network into 4 networks:
I got the IP: 195.232.176.0 /20
So by converting the IP into the following formation
[octal 1] . [octal 2] . [octal 3] . [octal 4]
11000011 . 11101000 . 10110000 . 00000000
By setting 1 in the first 20bits starting counting from the left I have:
==================20bits==============
11111111 . 11111111 . 1111 0000 . 00000000 = 225.225.240.0 (Subnet Mask)
So the four networks are :
Starting IP Address: 195.232.176.0 /20
195.232.x.0 /20
195.232.x.0 /20
195.232.x.0 /20
195.232.x.0 /20
Are the 4 networks correct?? My problem is on how will I put the x numbers with the data I have found!

A:

It's easy peasy once you know subnetting.
Let's have a closer look at the IP 195.232.176.0 /20. What is the full range?
195.232.176.0 to 195.232.191.255

So to divide the 195.232.176.0 /20 up into 4 subnets, you'll need a /22 mask for each subnet.
195.232.176.0/22 (195.232.176.0 to 195.232.179.255)
195.232.180.0/22 (195.232.180.0 to 195.232.183.255)
195.232.184.0/22 (195.232.184.0 to 195.232.187.255)
195.232.188.0/22 (195.232.188.0 to 195.232.191.255)

