def any_listname_of(resource)
      if resource::LIST_NAME.kind_of?(Array)
        resource::LIST_NAME.first # If is an array, any listname can be use
      else
        resource::LIST_NAME # If is not an array, just return the listname of resource
      end
    end
def any_listname_of(resource)
      if resource::LIST_NAME.kind_of?(Array)
        resource::LIST_NAME.first # If is an array, any listname can be use
      else
        resource::LIST_NAME # If is not an array, just return the listname of resource
      end
    end
Return any listname described on resource