\frac{F-32}{9}=\frac{C}{5}\\ \\ substituindo\&nbsp; C\&nbsp; por\&nbsp; 89\\ \\ \frac{F-32}{9}=\frac{89}{5}\\ \\(F-32).5}=9.89\\ \\ 5F-160 =801\\ \\5F=801+160\\ \\ F=\frac{961}{5}\\ \\\boxed{{\Large{\textbf{C=192,2\&ordm; \ }}}}