E = E o -0.0592 V log Q n E = 1.10V - 0.0592 V log [Cu][Zn 2+] 2[Cu 2+ ][Zn] E = 1.10V - 0.0592 V log [Zn 2+] 2[Cu 2+ ] E = 1.10V - 0.0592 V log [0.05