\displaystyle \sum_{n=0}^{\infty} \dfrac{3n - 2}{n!} = -2 + \sum_{n=1}^{\infty} \dfrac{3n - 2}{n!} = -2 + 3\sum_{n=1}^{\infty} \dfrac{1}{(n-1)!} - 2 \sum_{n=1}^{\infty} \dfrac{1}{n!}