( \sqrt{6x^2-7x+2})^2=1^2\\&amp;#10;6x^2-7x+2=1 \\&amp;#10;6x^2-7x+1=0\\&amp;#10;D=(-7)^2-4*6=49-24=25\\&amp;#10;x_1= \frac{7+5}{2*6}= \frac{12}{12}=1\\&amp;#10;\\&amp;#10;x_2= \frac{7-5}{12}= \frac{2}{12}= \frac{1}{6}     