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Chemical equilibrium
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In a chemical reaction, chemical equilibrium is the state in which both reactants and products are present in concentrations which have no further tendency to change with time, so that there is no observable change in the properties of the system.[1] Usually, this state results when the forward reaction proceeds at the same rate as the reverse reaction. The reaction rates of the forward and backward reactions are generally not zero, but equal. Thus, there are no net changes in the concentrations of the reactant(s) and product(s). Such a state is known as dynamic equilibrium.[2][3]
Contents
[hide]
1 Historical introduction
2 Thermodynamics
2.1 Addition of reactants or products
2.2 Treatment of activity
2.3 Concentration quotients
2.4 Metastable mixtures
3 Pure substances
4 Multiple equilibria
5 Effect of temperature
6 Effect of electric and magnetic fields
7 Types of equilibrium
8 Composition of a mixture
8.1 Mass-balance equations
8.1.1 Polybasic acids
8.1.2 Solution and precipitation
8.2 Minimization of Gibbs energy
9 See also
10 References
11 Further reading
Historical introduction[edit]
Burette, a common laboratory apparatus for carrying out titration, an important experimental technique in equilibrium and analytical chemistry.
The concept of chemical equilibrium was developed after Berthollet (1803) found that some chemical reactions are reversible.[4] For any reaction mixture to exist at equilibrium, the rates of the forward and backward (reverse) reactions are equal. In the following chemical equation with arrows pointing both ways to indicate equilibrium,[5] A and B are reactant chemical species, S and T are product species, and α, β, σ, and τ are the stoichiometric coefficients of the respective reactants and products:
α A + β B ⇌ σ S + τ T
The equilibrium concentration position of a reaction is said to lie "far to the right" if, at equilibrium, nearly all the reactants are consumed. Conversely the equilibrium position is said to be "far to the left" if hardly any product is formed from the reactants.
Guldberg and Waage (1865), building on Berthollet’s ideas, proposed the law of mass action:
forward reaction rate = k + A α B β backward reaction rate = k − S σ T τ {\displaystyle {\begin{aligned}{\ce {forward~reaction~rate}}&=k_{+}{\ce {A}}^{\alpha }{\ce {B}}^{\beta }\\{\ce {backward~reaction~rate}}&=k_{-}{\ce {S}}^{\sigma }{\ce {T}}^{\tau }\end{aligned}}}
where A, B, S and T are active masses and k+ and k− are rate constants. Since at equilibrium forward and backward rates are equal:
k + { A } α { B } β = k − { S } σ { T } τ {\displaystyle k_{+}\left\{{\ce {A}}\right\}^{\alpha }\left\{{\ce {B}}\right\}^{\beta }=k_{-}\left\{{\ce {S}}\right\}^{\sigma }\left\{{\ce {T}}\right\}^{\tau }\,}
and the ratio of the rate constants is also a constant, now known as an equilibrium constant.
K c = k + k − = { S } σ { T } τ { A } α { B } β {\displaystyle K_{c}={\frac {k_{+}}{k_{-}}}={\frac {\{{\ce {S}}\}^{\sigma }\{{\ce {T}}\}^{\tau }}{\{{\ce {A}}\}^{\alpha }\{{\ce {B}}\}^{\beta }}}}
By convention the products form the numerator. However, the law of mass action is valid only for concerted one-step reactions that proceed through a single transition state and is not valid in general because rate equations do not, in general, follow the stoichiometry of the reaction as Guldberg and Waage had proposed (see, for example, nucleophilic aliphatic substitution by SN1 or reaction of hydrogen and bromine to form hydrogen bromide). Equality of forward and backward reaction rates, however, is a necessary condition for chemical equilibrium, though it is not sufficient to explain why equilibrium occurs.
Despite the failure of this derivation, the equilibrium constant for a reaction is indeed a constant, independent of the activities of the various species involved, though it does depend on temperature as observed by the van 't Hoff equation. Adding a catalyst will affect both the forward reaction and the reverse reaction in the same way and will not have an effect on the equilibrium constant. The catalyst will speed up both reactions thereby increasing the speed at which equilibrium is reached.[2][6]
Although the macroscopic equilibrium concentrations are constant in time, reactions do occur at the molecular level. For example, in the case of acetic acid dissolved in water and forming acetate and hydronium ions,
CH3CO2H + H2O ⇌ CH
3CO−
2 + H3O+
a proton may hop from one molecule of acetic acid on to a water molecule and then on to an acetate anion to form another molecule of acetic acid and leaving the number of acetic acid molecules unchanged. This is an example of dynamic equilibrium. Equilibria, like the rest of thermodynamics, are statistical phenomena, averages of microscopic behavior.
Le Châtelier's principle (1884) gives an idea of the behavior of an equilibrium system when changes to its reaction conditions occur. If a dynamic equilibrium is disturbed by changing the conditions, the position of equilibrium moves to partially reverse the change. For example, adding more S from the outside will cause an excess of products, and the system will try to counteract this by increasing the reverse reaction and pushing the equilibrium point backward (though the equilibrium constant will stay the same).
If mineral acid is added to the acetic acid mixture, increasing the concentration of hydronium ion, the amount of dissociation must decrease as the reaction is driven to the left in accordance with this principle. This can also be deduced from the equilibrium constant expression for the reaction:
K = { CH 3 CO 2 − } { H 3 O + } { CH 3 CO 2 H } {\displaystyle K={\frac {\{{\ce {CH3CO2-}}\}\{{\ce {H3O+}}\}}{{\ce {\{CH3CO2H\}}}}}}
If {H3O+} increases {CH3CO2H} must increase and CH
3CO−
2 must decrease. The H2O is left out, as it is the solvent and its concentration remains high and nearly constant.
A quantitative version is given by the reaction quotient.
J. W. Gibbs suggested in 1873 that equilibrium is attained when the Gibbs free energy of the system is at its minimum value (assuming the reaction is carried out at constant temperature and pressure). What this means is that the derivative of the Gibbs energy with respect to reaction coordinate (a measure of the extent of reaction that has occurred, ranging from zero for all reactants to a maximum for all products) vanishes, signalling a stationary point. This derivative is called the reaction Gibbs energy (or energy change) and corresponds to the difference between the chemical potentials of reactants and products at the composition of the reaction mixture.[1] This criterion is both necessary and sufficient. If a mixture is not at equilibrium, the liberation of the excess Gibbs energy (or Helmholtz energy at constant volume reactions) is the "driving force" for the composition of the mixture to change until equilibrium is reached. The equilibrium constant can be related to the standard Gibbs free energy change for the reaction by the equation
Δ r G ⊖ = − R T ln  K eq {\displaystyle \Delta _{r}G^{\ominus }=-RT\ln K_{{\ce {eq}}}}
where R is the universal gas constant and T the temperature.
When the reactants are dissolved in a medium of high ionic strength the quotient of activity coefficients may be taken to be constant. In that case the concentration quotient, Kc,
K c = [ S ] σ [ T ] τ [ A ] α [ B ] β {\displaystyle K_{\ce {c}}={\frac {[{\ce {S}}]^{\sigma }[{\ce {T}}]^{\tau }}{[{\ce {A}}]^{\alpha }[{\ce {B}}]^{\beta }}}}
where [A] is the concentration of A, etc., is independent of the analytical concentration of the reactants. For this reason, equilibrium constants for solutions are usually determined in media of high ionic strength. Kc varies with ionic strength, temperature and pressure (or volume). Likewise Kp for gases depends on partial pressure. These constants are easier to measure and encountered in high-school chemistry courses.
Thermodynamics[edit]
At constant temperature and pressure, one must consider the Gibbs free energy, G, while at constant temperature and volume, one must consider the Helmholtz free energy: A, for the reaction; and at constant internal energy and volume, one must consider the entropy for the reaction: S.
The constant volume case is important in geochemistry and atmospheric chemistry where pressure variations are significant. Note that, if reactants and products were in standard state (completely pure), then there would be no reversibility and no equilibrium. Indeed, they would necessarily occupy disjoint volumes of space. The mixing of the products and reactants contributes a large entropy (known as entropy of mixing) to states containing equal mixture of products and reactants. The standard Gibbs energy change, together with the Gibbs energy of mixing, determine the equilibrium state.[7][8]
In this article only the constant pressure case is considered. The relation between the Gibbs free energy and the equilibrium constant can be found by considering chemical potentials.[1]
At constant temperature and pressure, the Gibbs free energy, G, for the reaction depends only on the extent of reaction: ξ (Greek letter xi), and can only decrease according to the second law of thermodynamics. It means that the derivative of G with ξ must be negative if the reaction happens; at the equilibrium the derivative being equal to zero.
( d G d ξ ) T , p = 0 {\displaystyle \left({\frac {dG}{d\xi }}\right)_{T,p}=0~} : equilibrium
In order to meet the thermodynamic condition for equilibrium, the Gibbs energy must be stationary, meaning that the derivative of G with respect to the extent of reaction: ξ, must be zero. It can be shown that in this case, the sum of chemical potentials of the products is equal to the sum of those corresponding to the reactants. Therefore, the sum of the Gibbs energies of the reactants must be the equal to the sum of the Gibbs energies of the products.
α μ A + β μ B = σ μ S + τ μ T {\displaystyle \alpha \mu _{\mathrm {A} }+\beta \mu _{\mathrm {B} }=\sigma \mu _{\mathrm {S} }+\tau \mu _{\mathrm {T} }\,}
where μ is in this case a partial molar Gibbs energy, a chemical potential. The chemical potential of a reagent A is a function of the activity, {A} of that reagent.
μ A = μ A ⊖ + R T ln  { A } {\displaystyle \mu _{\mathrm {A} }=\mu _{A}^{\ominus }+RT\ln\{\mathrm {A} \}\,}
(where μo
A is the standard chemical potential).
The definition of the Gibbs energy equation interacts with the fundamental thermodynamic relation to produce
d G = V d p − S d T + ∑ i = 1 k μ i d N i {\displaystyle dG=Vdp-SdT+\sum _{i=1}^{k}\mu _{i}dN_{i}} .
Inserting dNi = νi dξ into the above equation gives a Stoichiometric coefficient ( ν i {\displaystyle \nu _{i}~} ) and a differential that denotes the reaction occurring once (dξ). At constant pressure and temperature the above equations can be written as
( d G d ξ ) T , p = ∑ i = 1 k μ i ν i = Δ r G T , p {\displaystyle \left({\frac {dG}{d\xi }}\right)_{T,p}=\sum _{i=1}^{k}\mu _{i}\nu _{i}=\Delta _{\mathrm {r} }G_{T,p}} which is the "Gibbs free energy change for the reaction .
This results in:
Δ r G T , p = σ μ S + τ μ T − α μ A − β μ B {\displaystyle \Delta _{\mathrm {r} }G_{T,p}=\sigma \mu _{\mathrm {S} }+\tau \mu _{\mathrm {T} }-\alpha \mu _{\mathrm {A} }-\beta \mu _{\mathrm {B} }\,} .
By substituting the chemical potentials:
Δ r G T , p = ( σ μ S ⊖ + τ μ T ⊖ ) − ( α μ A ⊖ + β μ B ⊖ ) + ( σ R T ln  { S } + τ R T ln  { T } ) − ( α R T ln  { A } + β R T ln  { B } ) {\displaystyle \Delta _{\mathrm {r} }G_{T,p}=(\sigma \mu _{\mathrm {S} }^{\ominus }+\tau \mu _{\mathrm {T} }^{\ominus })-(\alpha \mu _{\mathrm {A} }^{\ominus }+\beta \mu _{\mathrm {B} }^{\ominus })+(\sigma RT\ln\{\mathrm {S} \}+\tau RT\ln\{\mathrm {T} \})-(\alpha RT\ln\{\mathrm {A} \}+\beta RT\ln\{\mathrm {B} \})} ,
the relationship becomes:
Δ r G T , p = ∑ i = 1 k μ i ⊖ ν i + R T ln  { S } σ { T } τ { A } α { B } β {\displaystyle \Delta _{\mathrm {r} }G_{T,p}=\sum _{i=1}^{k}\mu _{i}^{\ominus }\nu _{i}+RT\ln {\frac {\{\mathrm {S} \}^{\sigma }\{\mathrm {T} \}^{\tau }}{\{\mathrm {A} \}^{\alpha }\{\mathrm {B} \}^{\beta }}}}
∑ i = 1 k μ i ⊖ ν i = Δ r G ⊖ {\displaystyle \sum _{i=1}^{k}\mu _{i}^{\ominus }\nu _{i}=\Delta _{\mathrm {r} }G^{\ominus }} :
which is the standard Gibbs energy change for the reaction that can be calculated using thermodynamical tables. The reaction quotient is defined as:
Q r = { S } σ { T } τ { A } α { B } β {\displaystyle Q_{\mathrm {r} }={\frac {\{\mathrm {S} \}^{\sigma }\{\mathrm {T} \}^{\tau }}{\{\mathrm {A} \}^{\alpha }\{\mathrm {B} \}^{\beta }}}}
Therefore,
( d G d ξ ) T , p = Δ r G T , p = Δ r G ⊖ + R T ln  Q r {\displaystyle \left({\frac {dG}{d\xi }}\right)_{T,p}=\Delta _{\mathrm {r} }G_{T,p}=\Delta _{\mathrm {r} }G^{\ominus }+RT\ln Q_{\mathrm {r} }}
At equilibrium:
( d G d ξ ) T , p = Δ r G T , p = 0 {\displaystyle \left({\frac {dG}{d\xi }}\right)_{T,p}=\Delta _{\mathrm {r} }G_{T,p}=0}
leading to:
0 = Δ r G ⊖ + R T ln  K e q {\displaystyle 0=\Delta _{\mathrm {r} }G^{\ominus }+RT\ln K_{\mathrm {eq} }}
and
Δ r G ⊖ = − R T ln  K e q {\displaystyle \Delta _{\mathrm {r} }G^{\ominus }=-RT\ln K_{\mathrm {eq} }}
Obtaining the value of the standard Gibbs energy change, allows the calculation of the equilibrium constant.
Addition of reactants or products[edit]
For a reactional system at equilibrium: Qr = Keq; ξ = ξeq.
If are modified activities of constituents, the value of the reaction quotient changes and becomes different from the equilibrium constant: Qr ≠ Keq
( d G d ξ ) T , p = Δ r G ⊖ + R T ln  Q r {\displaystyle \left({\frac {dG}{d\xi }}\right)_{T,p}=\Delta _{\mathrm {r} }G^{\ominus }+RT\ln Q_{\mathrm {r} }~}
and
Δ r G ⊖ = − R T ln  K e q {\displaystyle \Delta _{\mathrm {r} }G^{\ominus }=-RT\ln K_{eq}~}
then
( d G d ξ ) T , p = R T ln  ( Q r K e q ) {\displaystyle \left({\frac {dG}{d\xi }}\right)_{T,p}=RT\ln \left({\frac {Q_{\mathrm {r} }}{K_{\mathrm {eq} }}}\right)~}
If activity of a reagent i increases

Q r = ∏ ( a j ) ν j ∏ ( a i ) ν i {\displaystyle Q_{\mathrm {r} }={\frac {\prod (a_{j})^{\nu _{j}}}{\prod (a_{i})^{\nu _{i}}}}~} , the reaction quotient decreases.
then
Q r < K e q {\displaystyle Q_{\mathrm {r} }<K_{\mathrm {eq} }~} and ( d G d ξ ) T , p < 0 {\displaystyle \left({\frac {dG}{d\xi }}\right)_{T,p}<0~}
The reaction will shift to the right (i.e. in the forward direction, and thus more products will form).
If activity of a product j increases
then
Q r > K e q {\displaystyle Q_{\mathrm {r} }>K_{\mathrm {eq} }~} and ( d G d ξ ) T , p > 0 {\displaystyle \left({\frac {dG}{d\xi }}\right)_{T,p}>0~}
The reaction will shift to the left (i.e. in the reverse direction, and thus less products will form).
Note that activities and equilibrium constants are dimensionless numbers.
Treatment of activity[edit]
The expression for the equilibrium constant can be rewritten as the product of a concentration quotient, Kc and an activity coefficient quotient, Γ.
K = [ S ] σ [ T ] τ . . . [ A ] α [ B ] β . . . × γ S σ γ T τ . . . γ A α γ B β . . . = K c Γ {\displaystyle K={\frac {[\mathrm {S} ]^{\sigma }[\mathrm {T} ]^{\tau }...}{[\mathrm {A} ]^{\alpha }[\mathrm {B} ]^{\beta }...}}\times {\frac {{\gamma _{\mathrm {S} }}^{\sigma }{\gamma _{\mathrm {T} }}^{\tau }...}{{\gamma _{\mathrm {A} }}^{\alpha }{\gamma _{\mathrm {B} }}^{\beta }...}}=K_{\mathrm {c} }\Gamma }
[A] is the concentration of reagent A, etc. It is possible in principle to obtain values of the activity coefficients, γ. For solutions, equations such as the Debye–Hückel equation or extensions such as Davies equation[9] Specific ion interaction theory or Pitzer equations[10] may be used.Software (below). However this is not always possible. It is common practice to assume that Γ is a constant, and to use the concentration quotient in place of the thermodynamic equilibrium constant. It is also general practice to use the term equilibrium constant instead of the more accurate concentration quotient. This practice will be followed here.
For reactions in the gas phase partial pressure is used in place of concentration and fugacity coefficient in place of activity coefficient. In the real world, for example, when making ammonia in industry, fugacity coefficients must be taken into account. Fugacity, f, is the product of partial pressure and fugacity coefficient. The chemical potential of a species in the gas phase is given by
μ = μ ⊖ + R T ln  ( f b a r ) = μ ⊖ + R T ln  ( p b a r ) + R T ln  γ {\displaystyle \mu =\mu ^{\ominus }+RT\ln \left({\frac {f}{\mathrm {bar} }}\right)=\mu ^{\ominus }+RT\ln \left({\frac {p}{\mathrm {bar} }}\right)+RT\ln \gamma }
so the general expression defining an equilibrium constant is valid for both solution and gas phases.
Concentration quotients[edit]
In aqueous solution, equilibrium constants are usually determined in the presence of an "inert" electrolyte such as sodium nitrate NaNO3 or potassium perchlorate KClO4. The ionic strength of a solution is given by
I = 1 2 ∑ i = 1 N c i z i 2 {\displaystyle I={\frac {1}{2}}\sum _{i=1}^{N}c_{i}z_{i}^{2}}
where ci and zi stand for the concentration and ionic charge of ion type i, and the sum is taken over all the N types of charged species in solution. When the concentration of dissolved salt is much higher than the analytical concentrations of the reagents, the ions originating from the dissolved salt determine the ionic strength, and the ionic strength is effectively constant. Since activity coefficients depend on ionic strength the activity coefficients of the species are effectively independent of concentration. Thus, the assumption that Γ is constant is justified. The concentration quotient is a simple multiple of the equilibrium constant.[11]
K c = K Γ {\displaystyle K_{\mathrm {c} }={\frac {K}{\Gamma }}}
However, Kc will vary with ionic strength. If it is measured at a series of different ionic strengths the value can be extrapolated to zero ionic strength.[10] The concentration quotient obtained in this manner is known, paradoxically, as a thermodynamic equilibrium constant.
To use a published value of an equilibrium constant in conditions of ionic strength different from the conditions used in its determination, the value should be adjustedSoftware (below).
Metastable mixtures[edit]
A mixture may appear to have no tendency to change, though it is not at equilibrium. For example, a mixture of SO2 and O2 is metastable as there is a kinetic barrier to formation of the product, SO3.
2 SO2 + O2 ⇌ 2 SO3
The barrier can be overcome when a catalyst is also present in the mixture as in the contact process, but the catalyst does not affect the equilibrium concentrations.
Likewise, the formation of bicarbonate from carbon dioxide and water is very slow under normal conditions
CO2 + 2 H2O ⇌ HCO−
3 + H3O+
but almost instantaneous in the presence of the catalytic enzyme carbonic anhydrase.
Pure substances[edit]
When pure substances (liquids or solids) are involved in equilibria their activities do not appear in the equilibrium constant[12] because their numerical values are considered one.
Applying the general formula for an equilibrium constant to the specific case of a dilute solution of acetic acid in water one obtains
CH3CO2H + H2O ⇌ CH3CO2− + H3O+
K c = [ C H 3 C O 2 − ] [ H 3 O + ] [ C H 3 C O 2 H ] [ H 2 O ] {\displaystyle K_{\mathrm {c} }={\frac {\mathrm {[{CH_{3}CO_{2}}^{-}][{H_{3}O}^{+}]} }{\mathrm {[{CH_{3}CO_{2}H}][{H_{2}O}]} }}}
For all but very concentrated solutions, the water can be considered a "pure" liquid, and therefore it has an activity of one. The equilibrium constant expression is therefore usually written as
K = [ C H 3 C O 2 − ] [ H 3 O + ] [ C H 3 C O 2 H ] = K c {\displaystyle K={\frac {\mathrm {[{CH_{3}CO_{2}}^{-}][{H_{3}O}^{+}]} }{\mathrm {[{CH_{3}CO_{2}H}]} }}=K_{\mathrm {c} }} .
A particular case is the self-ionization of water itself
2 H2O ⇌ H3O+ + OH−
Because water is the solvent, and has an activity of one, the self-ionization constant of water is defined as
K w = [ H + ] [ O H − ] {\displaystyle K_{\mathrm {w} }=\mathrm {[H^{+}][OH^{-}]} }
It is perfectly legitimate to write [H+] for the hydronium ion concentration, since the state of solvation of the proton is constant (in dilute solutions) and so does not affect the equilibrium concentrations. Kw varies with variation in ionic strength and/or temperature.
The concentrations of H+ and OH− are not independent quantities. Most commonly [OH−] is replaced by Kw[H+]−1 in equilibrium constant expressions which would otherwise include hydroxide ion.
Solids also do not appear in the equilibrium constant expression, if they are considered to be pure and thus their activities taken to be one. An example is the Boudouard reaction:[12]
2 CO ⇌ CO2 + C
for which the equation (without solid carbon) is written as:
K c = [ C O 2 ] [ C O ] 2 {\displaystyle K_{\mathrm {c} }={\frac {\mathrm {[CO_{2}]} }{\mathrm {[CO]^{2}} }}}
Multiple equilibria[edit]
Consider the case of a dibasic acid H2A. When dissolved in water, the mixture will contain H2A, HA− and A2−. This equilibrium can be split into two steps in each of which one proton is liberated.
H 2 A ↽ − − ⇀ HA − + H + : K 1 = [ HA − ] [ H + ] [ H 2 A ] HA − ↽ − − ⇀ A 2 − + H + : K 2 = [ A 2 − ] [ H + ] [ HA − ] {\displaystyle {\begin{array}{rl}{\ce {H2A<=>{HA^{-}}+{H+}}}:&K_{1}={\frac {\ce {[HA-][H+]}}{\ce {[H2A]}}}\\{\ce {HA-<=>{A^{2-}}+{H+}}}:&K_{2}={\frac {\ce {[A^{2-}][H+]}}{\ce {[HA-]}}}\end{array}}}
K1 and K2 are examples of stepwise equilibrium constants. The overall equilibrium constant, βD, is product of the stepwise constants.
H 2 A ↽ − − ⇀ A 2 − + 2 H + {\displaystyle {\ce {{H2A}<=>{A^{2-}}+{2H+}}}} : β D = [ A 2 − ] [ H + ] 2 [ H 2 A ] = K 1 K 2 {\displaystyle \beta _{{\ce {D}}}={\frac {{\ce {[A^{2-}][H^+]^2}}}{{\ce {[H_2A]}}}}=K_{1}K_{2}}
Note that these constants are dissociation constants because the products on the right hand side of the equilibrium expression are dissociation products. In many systems, it is preferable to use association constants.
A 2 − + H + ↽ − − ⇀ HA − : β 1 = [ HA − ] [ A 2 − ] [ H + ] A 2 − + 2 H + ↽ − − ⇀ H 2 A : β 2 = [ H 2 A ] [ A 2 − ] [ H + ] 2 {\displaystyle {\begin{array}{ll}{\ce {{A^{2-}}+{H+}<=>HA-}}:&\beta _{1}={\frac {\ce {[HA^{-}]}}{\ce {[A^{2-}][H+]}}}\\{\ce {{A^{2-}}+{2H+}<=>H2A}}:&\beta _{2}={\frac {\ce {[H2A]}}{\ce {[A^{2-}][H+]^{2}}}}\end{array}}}
β1 and β2 are examples of association constants. Clearly β1 = 1/K2 and β2 = 1/βD; log β1 = pK2 and log β2 = pK2 + pK1[13] For multiple equilibrium systems, also see: theory of Response reactions.
Effect of temperature[edit]
The effect of changing temperature on an equilibrium constant is given by the van 't Hoff equation
d ln  K d T = Δ H m ⊖ R T 2 {\displaystyle {\frac {d\ln K}{dT}}={\frac {\Delta H_{\mathrm {m} }^{\ominus }}{RT^{2}}}}
Thus, for exothermic reactions (ΔH is negative), K decreases with an increase in temperature, but, for endothermic reactions, (ΔH is positive) K increases with an increase temperature. An alternative formulation is
d ln  K d ( T − 1 ) = − Δ H m ⊖ R {\displaystyle {\frac {d\ln K}{d(T^{-1})}}=-{\frac {\Delta H_{\mathrm {m} }^{\ominus }}{R}}}
At first sight this appears to offer a means of obtaining the standard molar enthalpy of the reaction by studying the variation of K with temperature. In practice, however, the method is unreliable because error propagation almost always gives very large errors on the values calculated in this way.
Effect of electric and magnetic fields[edit]
The effect of electric field on equilibrium has been studied by Manfred Eigen[citation needed] among others.
Types of equilibrium[edit]
Haber–Bosch process
# N2 (g) ⇌ N2 (adsorbed)
N2 (adsorbed) ⇌ 2 N (adsorbed)
H2 (g) ⇌ H2 (adsorbed)
H2 (adsorbed) ⇌ 2 H (adsorbed)
N (adsorbed) + 3 H(adsorbed) ⇌ NH3 (adsorbed)
NH3 (adsorbed) ⇌ NH3 (g)
In the gas phase: rocket engines[14]
The industrial synthesis such as ammonia in the Haber–Bosch process (depicted right) takes place through a succession of equilibrium steps including adsorption processes
Atmospheric chemistry
Seawater and other natural waters: chemical oceanography
Distribution between two phases
log D distribution coefficient: important for pharmaceuticals where lipophilicity is a significant property of a drug
Liquid–liquid extraction, Ion exchange, Chromatography
Solubility product
Uptake and release of oxygen by hemoglobin in blood
Acid–base equilibria: acid dissociation constant, hydrolysis, buffer solutions, indicators, acid–base homeostasis
Metal–ligand complexation: sequestering agents, chelation therapy, MRI contrast reagents, Schlenk equilibrium
Adduct formation: host–guest chemistry, supramolecular chemistry, molecular recognition, dinitrogen tetroxide
In certain oscillating reactions, the approach to equilibrium is not asymptotically but in the form of a damped oscillation .[12]
The related Nernst equation in electrochemistry gives the difference in electrode potential as a function of redox concentrations.
When molecules on each side of the equilibrium are able to further react irreversibly in secondary reactions, the final product ratio is determined according to the Curtin–Hammett principle.
In these applications, terms such as stability constant, formation constant, binding constant, affinity constant, association/dissociation constant are used. In biochemistry, it is common to give units for binding constants, which serve to define the concentration units used when the constant’s value was determined.
Composition of a mixture[edit]
When the only equilibrium is that of the formation of a 1:1 adduct as the composition of a mixture, there are many ways that the composition of a mixture can be calculated. For example, see ICE table for a traditional method of calculating the pH of a solution of a weak acid.
There are three approaches to the general calculation of the composition of a mixture at equilibrium.
The most basic approach is to manipulate the various equilibrium constants until the desired concentrations are expressed in terms of measured equilibrium constants (equivalent to measuring chemical potentials) and initial conditions.
Minimize the Gibbs energy of the system.[15][16]
Satisfy the equation of mass balance. The equations of mass balance are simply statements that demonstrate that the total concentration of each reactant must be constant by the law of conservation of mass.
Mass-balance equations[edit]
In general, the calculations are rather complicated or complex. For instance, in the case of a dibasic acid, H2A dissolved in water the two reactants can be specified as the conjugate base, A2−, and the proton, H+. The following equations of mass-balance could apply equally well to a base such as 1,2-diaminoethane, in which case the base itself is designated as the reactant A:
T A = [ A ] + [ H A ] + [ H 2 A ] {\displaystyle T_{\mathrm {A} }=\mathrm {[A]+[HA]+[H_{2}A]} \,}
T H = [ H ] + [ H A ] + 2 [ H 2 A ] − [ O H ] {\displaystyle T_{\mathrm {H} }=\mathrm {[H]+[HA]+2[H_{2}A]-[OH]} \,}
With TA the total concentration of species A. Note that it is customary to omit the ionic charges when writing and using these equations.
When the equilibrium constants are known and the total concentrations are specified there are two equations in two unknown "free concentrations" [A] and [H]. This follows from the fact that [HA] = β1[A][H], [H2A] = β2[A][H]2 and [OH] = Kw[H]−1
T A = [ A ] + β 1 [ A ] [ H ] + β 2 [ A ] [ H ] 2 {\displaystyle T_{\mathrm {A} }=\mathrm {[A]} +\beta _{1}\mathrm {[A][H]} +\beta _{2}\mathrm {[A][H]} ^{2}\,}
T H = [ H ] + β 1 [ A ] [ H ] + 2 β 2 [ A ] [ H ] 2 − K w [ H ] − 1 {\displaystyle T_{\mathrm {H} }=\mathrm {[H]} +\beta _{1}\mathrm {[A][H]} +2\beta _{2}\mathrm {[A][H]} ^{2}-K_{w}[\mathrm {H} ]^{-1}\,}
so the concentrations of the "complexes" are calculated from the free concentrations and the equilibrium constants. General expressions applicable to all systems with two reagents, A and B would be
T A = [ A ] + ∑ i p i β i [ A ] p i [ B ] q i {\displaystyle T_{\mathrm {A} }=[\mathrm {A} ]+\sum _{i}p_{i}\beta _{i}[\mathrm {A} ]^{p_{i}}[\mathrm {B} ]^{q_{i}}}
T B = [ B ] + ∑ i q i β i [ A ] p i [ B ] q i {\displaystyle T_{\mathrm {B} }=[\mathrm {B} ]+\sum _{i}q_{i}\beta _{i}[\mathrm {A} ]^{p_{i}}[\mathrm {B} ]^{q_{i}}}
It is easy to see how this can be extended to three or more reagents.
Polybasic acids[edit]
Species concentrations during hydrolysis of the aluminium.
The composition of solutions containing reactants A and H is easy to calculate as a function of p[H]. When [H] is known, the free concentration [A] is calculated from the mass-balance equation in A.
The diagram alongside, shows an example of the hydrolysis of the aluminium Lewis acid Al3+(aq)[17] shows the species concentrations for a 5 × 10−6 M solution of an aluminium salt as a function of pH. Each concentration is shown as a percentage of the total aluminium.
Solution and precipitation[edit]
The diagram above illustrates the point that a precipitate that is not one of the main species in the solution equilibrium may be formed. At pH just below 5.5 the main species present in a 5 μM solution of Al3+ are aluminium hydroxides Al(OH)2+, AlOH+
2 and Al
13(OH)7+
32, but on raising the pH Al(OH)3 precipitates from the solution. This occurs because Al(OH)3 has a very large lattice energy. As the pH rises more and more Al(OH)3 comes out of solution. This is an example of Le Châtelier's principle in action: Increasing the concentration of the hydroxide ion causes more aluminium hydroxide to precipitate, which removes hydroxide from the solution. When the hydroxide concentration becomes sufficiently high the soluble aluminate, Al(OH)−
4, is formed.
Another common instance where precipitation occurs is when a metal cation interacts with an anionic ligand to form an electrically neutral complex. If the complex is hydrophobic, it will precipitate out of water. This occurs with the nickel ion Ni2+ and dimethylglyoxime, (dmgH2): in this case the lattice energy of the solid is not particularly large, but it greatly exceeds the energy of solvation of the molecule Ni(dmgH)2.
Minimization of Gibbs energy[edit]
At equilibrium, at a specified temperature and pressure, the Gibbs energy G is at a minimum:
d G = ∑ j = 1 m μ j d N j = 0 {\displaystyle dG=\sum _{j=1}^{m}\mu _{j}\,dN_{j}=0}
For a closed system, no particles may enter or leave, although they may combine in various ways. The total number of atoms of each element will remain constant. This means that the minimization above must be subjected to the constraints:
∑ j = 1 m a i j N j = b i 0 {\displaystyle \sum _{j=1}^{m}a_{ij}N_{j}=b_{i}^{0}}
where aij is the number of atoms of element i in molecule j and b0
i is the total number of atoms of element i, which is a constant, since the system is closed. If there are a total of k types of atoms in the system, then there will be k such equations. If ions are involved, an additional row is added to the aij matrix specifying the respective charge on each molecule which will sum to zero.
This is a standard problem in optimisation, known as constrained minimisation. The most common method of solving it is using the method of Lagrange multipliers, also known as undetermined multipliers (though other methods may be used).
Define:
G = G + ∑ i = 1 k λ i ( ∑ j = 1 m a i j N j − b i 0 ) = 0 {\displaystyle {\mathcal {G}}=G+\sum _{i=1}^{k}\lambda _{i}\left(\sum _{j=1}^{m}a_{ij}N_{j}-b_{i}^{0}\right)=0}
where the λi are the Lagrange multipliers, one for each element. This allows each of the Nj and λj to be treated independently, and it can be shown using the tools of multivariate calculus that the equilibrium condition is given by
0 = ∂ G ∂ N j = μ j + ∑ i = 1 k λ i a i j {\displaystyle 0={\frac {\partial {\mathcal {G}}}{\partial N_{j}}}=\mu _{j}+\sum _{i=1}^{k}\lambda _{i}a_{ij}}
0 = ∂ G ∂ λ i = ∑ j = 1 m a i j N j − b i 0 {\displaystyle 0={\frac {\partial {\mathcal {G}}}{\partial \lambda _{i}}}=\sum _{j=1}^{m}a_{ij}N_{j}-b_{i}^{0}}
(For proof see Lagrange multipliers.) This is a set of (m + k) equations in (m + k) unknowns (the Nj and the λi) and may, therefore, be solved for the equilibrium concentrations Nj as long as the chemical potentials are known as functions of the concentrations at the given temperature and pressure. (See Thermodynamic databases for pure substances.) Note that the second equation is just the initial constraints for minimization.
This method of calculating equilibrium chemical concentrations is useful for systems with a large number of different molecules. The use of k atomic element conservation equations for the mass constraint is straightforward, and replaces the use of the stoichiometric coefficient equations.[14]. The results are consistent with those specified by chemical equations. For example, if equilibrium is specified by a single chemical equation: [18],
∑ j = 0 m ν j R j = 0 {\displaystyle \sum _{j=0}^{m}\nu _{j}R_{j}=0}
where νj is the stochiometric coefficient for the j th molecule (negative for reactants, positive for products) and Rj is the symbol for the j th molecule, a properly balanced equation will obey:
∑ j = 1 m a i j ν j = 0 {\displaystyle \sum _{j=1}^{m}a_{ij}\nu _{j}=0}
Multiplying the first equilibrium condition by νj yields
0 = ∑ j = 1 m ν j μ j + ∑ j = 1 m ∑ i = 1 k ν j λ i a i j = ∑ j = 1 m ν j μ j {\displaystyle 0=\sum _{j=1}^{m}\nu _{j}\mu _{j}+\sum _{j=1}^{m}\sum _{i=1}^{k}\nu _{j}\lambda _{i}a_{ij}=\sum _{j=1}^{m}\nu _{j}\mu _{j}}
As above, defining ΔG
Δ G = ∑ j = 1 m ν j μ j = ∑ j = 1 m ν j ( μ j ⊖ + R T ln  ( { R j } ) ) = Δ G ⊖ + R T ln  ( ∏ j = 1 m { R j } ν j ) = Δ G ⊖ + R T ln  ( Q r ) {\displaystyle \Delta G=\sum _{j=1}^{m}\nu _{j}\mu _{j}=\sum _{j=1}^{m}\nu _{j}(\mu _{j}^{\ominus }+RT\ln(\{R_{j}\}))=\Delta G^{\ominus }+RT\ln \left(\prod _{j=1}^{m}\{R_{j}\}^{\nu _{j}}\right)=\Delta G^{\ominus }+RT\ln(Q_{r})}
which will be zero at equilibrium.
See also[edit]
Acidosis
Alkalosis
Arterial blood gas
Benesi–Hildebrand method
Determination of equilibrium constants
Equilibrium constant
Henderson–Hasselbalch equation
Michaelis–Menten kinetics
pCO2
pH
pKa
Redox equilibria
Steady state (chemistry)
Thermodynamic databases for pure substances
Non-random two-liquid model (NRTL model) - Phase equilibrium calculations
UNIQUAC model - Phase equilibrium calculations
References[edit]
^ Jump up to: a b c Atkins, Peter; De Paula, Julio (2006). Atkins' Physical Chemistry (8th ed.). W. H. Freeman. pp. 200–202. ISBN 0-7167-8759-8.
^ Jump up to: a b Atkins, Peter W.; Jones, Loretta. Chemical Principles: The Quest for Insight (2nd ed.). ISBN 0-7167-9903-0.
Jump up ^ IUPAC, Compendium of Chemical Terminology, 2nd ed. (the "Gold Book") (1997). Online corrected version: (2006–) "chemical equilibrium".
Jump up ^ Berthollet, C.L. (1803). Essai de statique chimique [Essay on chemical statics] (in French). Paris, France: Firmin Didot. On pp. 404–407, Berthellot mentions that when he accompanied Napoleon on his expedition to Egypt, he (Berthellot) visited Lake Natron and found sodium carbonate along its shores. He realized that this was a product of the reverse of the usual reaction Na2CO3 + CaCl2 → 2NaCl + CaCO3↓ and therefore that the final state of a reaction was a state of equilibrium between two opposing processes. From p. 405: " … la décomposition du muriate de soude continue donc jusqu'à ce qu'il se soit formé assez de muriate de chaux, parce que l'acide muriatique devant se partager entre les deux bases en raison de leur action, il arrive un terme où leurs forces se balancent." ( … the decomposition of the sodium chloride thus continues until enough calcium chloride is formed, because the hydrochloric acid must be shared between the two bases in the ratio of their action [i.e., capacity to react]; it reaches an end [point] at which their forces are balanced.)
Jump up ^ The notation ⇌ was proposed in 1884 by the Dutch chemist Jacobus Henricus van 't Hoff. See: van 't Hoff, J.H. (1884). Études de Dynamique Chemique [Studies of chemical dynamics] (in French). Amsterdam, Netherlands: Frederik Muller & Co. pp. 4–5. Van 't Hoff called reactions that didn't proceed to completion "limited reactions". From pp. 4–5: "Or M. Pfaundler a relié ces deux phénomênes … s'accomplit en même temps dans deux sens opposés." (Now Mr. Pfaundler has joined these two phenomena in a single concept by considering the observed limit as the result of two opposing reactions, driving the one in the example cited to the formation of sea salt [i.e., NaCl] and nitric acid, [and] the other to hydrochloric acid and sodium nitrate. This consideration, which experiment validates, justifies the expression "chemical equilibrium", which is used to characterize the final state of limited reactions. I would propose to translate this expression by the following symbol:
HCl + NO3 Na ⇌ NO3 H + Cl Na .
I thus replace, in this case, the = sign in the chemical equation by the sign ⇌, which in reality doesn't express just equality but shows also the direction of the reaction. This clearly expresses that a chemical action occurs simultaneously in two opposing directions.)
Jump up ^ Brady, James E. Chemistry: Matter and Its Changes (4th ed.). Fred Senese. ISBN 0-471-21517-1.
Jump up ^ Schultz, Mary Jane (1999). "Why Equilibrium? Understanding Entropy of Mixing". Journal of Chemical Education. 76 (10): 1391. Bibcode:1999JChEd..76.1391S. doi:10.1021/ed076p1391.
Jump up ^ Clugston, Michael J. (1990). "A mathematical verification of the second law of thermodynamics from the entropy of mixing". Journal of Chemical Education. 67 (3): 203. Bibcode:1990JChEd..67Q.203C. doi:10.1021/ed067p203.
Jump up ^ Davies, C. W. (1962). Ion Association. Butterworths.
^ Jump up to: a b Grenthe, I.; Wanner, H. "Guidelines for the extrapolation to zero ionic strength" (PDF).
Jump up ^ Rossotti, F. J. C.; Rossotti, H. (1961). The Determination of Stability Constants. McGraw-Hill.
^ Jump up to: a b c Concise Encyclopedia Chemistry. 1994. ISBN 0-89925-457-8.
Jump up ^ Beck, M. T.; Nagypál, I. (1990). Chemistry of Complex Equilibria (2nd ed.). Budapest: Akadémiai Kaidó.
^ Jump up to: a b "Computer Program for Calculation of Complex Chemical Equilibrium Compositions and Applications" (PDF). NASA Reference publication 1311. NASA. 1994.
Jump up ^ Smith, W. R.; Missen, R. W. (1991). Chemical Reaction Equilibrium Analysis: Theory and Algorithms (Reprinted ed.). Malabar, FL: Krieger Publishing.
Jump up ^ "Mathtrek Systems".
Jump up ^ The diagram was created with the program HySS
Jump up ^ C. Kittel, H. Kroemer (1980). "9". Thermal Physics (2 ed.). W. H. Freeman Company. ISBN 0-7167-1088-9.
Further reading[edit]
Library resources about
Chemical equilibrium
Resources in your library
Van Zeggeren, F.; Storey, S. H. (1970). The Computation of Chemical Equilibria. Cambridge University Press. Mainly concerned with gas-phase equilibria.
Leggett, D. J., ed. (1985). Computational Methods for the Determination of Formation Constants. Plenum Press.
Martell, A. E.; Motekaitis, R. J. (1992). The Determination and Use of Stability Constants. Wiley-VCH.
Gans, P. (2004). Stability Constants: Determination and Uses (CD-ROM)|format= requires |url= (help). Leeds: Protonic Software.
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text:
I'm Like a Bird
From Wikipedia, the free encyclopedia
Jump to: navigation, search
"I'm Like a Bird"
Single by Nelly Furtado
from the album Whoa, Nelly!
B-side
"I Feel You"
"Party (Reprise)"
"My Love Grows Deeper"
Released
October 24, 2000 (2000-10-24)
Format
CD single
Recorded
1999
Genre
Pop
folk
R&B
Length
4:03
Label
DreamWorks
Songwriter(s)
Nelly Furtado
Producer(s)
Gerald Eaton
Brian West
Nelly Furtado singles chronology
"I'm Like a Bird"
(2000) "Turn Off the Light"
(2001)
"I'm Like a Bird"
(2000) "Turn Off the Light"
(2001)
Alternative cover
European cover
Audio sample
file
help
Music video
"I'm Like a Bird" on YouTube
"I'm Like a Bird" is a song written by Canadian singer-songwriter Nelly Furtado, and produced by Gerald Eaton and Brian West, as the first single from her first album, Whoa, Nelly!.
It was one of the most successful singles of 2001, peaking at number one on the Canadian Singles Chart, as well as number two in Australia and New Zealand, number five in the United Kingdom, and number nine in the United States.
The song received very positive reviews from music critics for Furtado's singing and the empowering lyrics, and became one of the most critically acclaimed songs of 2001. Many also consider it to be her signature song; Furtado herself commented "There's a simplicity about it that I love," and "It's my freedom song". The song was nominated for the Grammy Award for Song of the Year and won the Grammy Award for Best Female Pop Vocal Performance, making Furtado the first female act to win the award for her debut single since Mariah Carey did so ten years earlier and the last to be awarded to a Canadian artist winner in the category. It also won the Juno Award for Single of the Year.
Contents
[hide]
1 Music Theory
2 Artist Response
3 Music video
4 Track listing
5 Personnel
6 Official versions
7 Release history
8 Charts
8.1 Weekly charts
8.2 Year-end charts
9 Certifications
10 References
11 External links
Music Theory[edit]
"I'm Like a Bird" is composed common time in the key of B♭ major.[1] The song moves at 90 beats per minute, and Furtado's voice spans around an octave and a half, from F3 to B♭4.[1] It is written in verse-chorus form, with a bridge before the second chorus.[1]
Artist Response[edit]
In 2006 Furtado said of the song, "I've heard it sung at karaoke or by cover bands and it was awesome — I was like, wow, I've got one of those songs. Somebody once called it a 'hairbrush song', one that girls and guys sing in front of the mirror with their hairbrush. I just think I'm lucky I have it — it's paying the bills!"[2]
Music video[edit]
The music video for "I'm Like a Bird" was directed by Francis Lawrence.[3] The video begins in the sky where the camera slowly pans down onto Furtado, who is lying in the grass. It then shows her singing on a tree trunk in mid-air. In the chorus she gets up and starts singing to the camera while birds are flying around her. The second verse shows her sitting in mid-air in a forest, while singing to the camera. The chorus consists of flashes of Furtado singing in mid-air, again, while leaning on the tree trunk. During the bridge she is singing to a bug while her eyes change colour. The conclusion of the video shows her falling backwards from a branch into a crowd as she sings the final chorus of the song. The last shot pans out to reveal a crowd of tens of thousands.
There was made an edited version of the music video for European VH1, where some scenes where changed.
Track listing[edit]
UK CD single
"I'm Like a Bird" (LP version) – 4:02
"Party" (Reprise) (non-LP version) – 4:53
"My Love Grows Deeper" (non-LP version) – 4:54
"I'm Like a Bird" (video) – 4:02
German 2-track single
"I'm Like a Bird" (LP version) – 4:02
"Party" (Reprise) (non-LP version) – 4:53
German 4-track single
"I'm Like a Bird" (LP version) – 4:02
"Party" (Reprise) (non-LP version) – 4:53
"My Love Grows Deeper" (non-LP version) – 4:54
"I Feel You" (featuring Esthero) – 4:08
Personnel[edit]
Credits are adapted from the Whoa, Nelly! album liner notes.[4]
Nelly Furtado – songwriting, co-producer, lead vocals, background vocals
Brian West – producer, acoustic guitar, engineering, programming, recording
Gerald Eaton – producer, programming
Russ Miller – drums
Mike Elizondo – bass
Brad Haehnel – shaker, mixing, engineering, recording
Allan Molnar – vibraphone, acoustic guitar, synthesizer
John Knupp – second engineering
Official versions[edit]
"I'm Like a Bird" (Junior Vasquez Club Anthem Remix) – 10:21
"I'm Like a Bird" (Junior Vasquez Club Anthem Padapella) – 9:12
"I'm Like a Bird" (Junior Vasquez Earth Anthem Radio Mix) – 6:30
"I'm Like a Bird" (Gavo's Martini Bar mix) – 6:56
"I'm Like a Bird" (Your Mom's Mix) - 7:27
"I'm Like a Bird" (Moon mix) – 4:27
"I'm Like a Bird" (Tara remix)
"I'm Like a Bird" (F Man remix)
"I'm Like a Bird" (Vadco Martini mix)
"I'm Like a Bird" (Bubbling Reggae remix)
"I'm Like a Bird" (Asha vs. Nelly Remix) – 5:33
"I'm Like a Bird" (Studio Version from Get Loose Tour) – 5:51
"I'm Like a Bird" (Radio promo) – 4:02
"I'm Like a Bird" (LP version) – 4:04
"I'm Like a Bird" (Acoustic version) – 4:29
"I'm Like a Bird" (Piano version)
"I'm Like a Bird" (Karaoke version)
"I'm Like a Bird" (Instrumental version)
"I'm Like a Bird" (Element 101 Cover from Punk Goes Pop)
Release history[edit]
Region
Date
Label
United States October 24, 2000 (2000-10-24) DreamWorks
Canada November 28, 2000 (2000-11-28) Universal Music
Europe February 19, 2001 (2001-02-19)
Australia February 26, 2001 (2001-02-26)
United Kingdom
Charts[edit]
Weekly charts[edit]
Chart (2000–01)[5]
Peak
position
Australia (ARIA)[6] 2
Austria (Ö3 Austria Top 40)[7] 41
Belgium (Ultratop 50 Flanders)[8] 16
Belgium (Ultratop 50 Wallonia)[9] 19
Brazil (ABPD)[10] 3
Canada (Canadian Hot 100)[11] 1
Denmark (Tracklisten)[12] 13
France (SNEP)[13] 33
Germany (Official German Charts)[14] 41
Ireland (IRMA)[15] 4
Italy (FIMI)[16] 16
Netherlands (Single Top 100)[17] 8
New Zealand (Recorded Music NZ)[18] 2
Norway (VG-lista)[19] 17
Portugal (Portuguese Singles Chart)[20] 4
Romania (Romanian Top 100)[21] 24
Sweden (Sverigetopplistan)[22] 16
Switzerland (Schweizer Hitparade)[23] 17
UK Singles (Official Charts Company)[24] 5
US Billboard Hot 100[25] 9
US Mainstream Top 40 (Billboard)[26] 6
US Adult Top 40 (Billboard)[27] 5
US Adult Contemporary (Billboard)[28] 26
Year-end charts[edit]
Chart (2001)
Position
Australian Singles (ARIA)[29] 7
New Zealand (Recorded Music NZ)[30] 8
UK (OCC)[31] 33
US Billboard Hot 100[32] 43
Certifications[edit]
Region
Certification
Certified units/Sales
Australia (ARIA)[33]
2× Platinum 140,000^
United Kingdom (BPI)[34]
Gold 400,000^
^shipments figures based on certification alone
References[edit]
^ Jump up to: a b c Sheet music for "I'm Like a Bird". Nelstar Publishing. 2001.
Jump up ^ de Silverio, Victoria. "Nelly Furtado: Free As A Bird" Archived 2007-09-30 at the Wayback Machine.. Blender. July 2006. Retrieved 18 September 2006.
Jump up ^ Method Studios - Nelly Furtado "I'm Like a Bird" Archived 2007-10-26 at the Wayback Machine.
Jump up ^ (2000) Album notes for Whoa, Nelly! by Nelly Furtado [liner notes]. DreamWorks Records.
Jump up ^ "International Chart Performance". Swisscharts. Retrieved 2008-03-26.
Jump up ^ "Australian-charts.com – Nelly Furtado – I'm Like A Bird". ARIA Top 50 Singles.
Jump up ^ "Austriancharts.at – Nelly Furtado – I'm Like A Bird" (in German). Ö3 Austria Top 40.
Jump up ^ "Ultratop.be – Nelly Furtado – I'm Like A Bird" (in Dutch). Ultratop 50.
Jump up ^ "Ultratop.be – Nelly Furtado – I'm Like A Bird" (in French). Ultratop 50.
Jump up ^ "Brazil" (PDF). ABPD. October 6, 2001. Retrieved April 1, 2014.
Jump up ^ "Nelly Furtado Chart History (Canadian Hot 100)". Billboard.
Jump up ^ "Danishcharts.com – Nelly Furtado – I'm Like A Bird". Tracklisten.
Jump up ^ "Lescharts.com – Nelly Furtado – I'm Like A Bird" (in French). Les classement single.
Jump up ^ "Musicline.de – Furtado,Nelly Single-Chartverfolgung" (in German). Media Control Charts. PhonoNet GmbH.
Jump up ^ "Chart Track: Week 15x, 2001". Irish Singles Chart.
Jump up ^ "Italiancharts.com – Nelly Furtado – I'm Like A Bird". Top Digital Download.
Jump up ^ "Dutchcharts.nl – Nelly Furtado – I'm Like A Bird" (in Dutch). Single Top 100.
Jump up ^ "Charts.org.nz – Nelly Furtado – I'm Like A Bird". Top 40 Singles.
Jump up ^ "Norwegiancharts.com – Nelly Furtado – I'm Like A Bird". VG-lista.
Jump up ^ "Top40-charts.com". Retrieved November 24, 2015.
Jump up ^ Romanian 2001 end-of-year charts
Jump up ^ "Swedishcharts.com – Nelly Furtado – I'm Like A Bird". Singles Top 100.
Jump up ^ "Swisscharts.com – Nelly Furtado – I'm Like A Bird". Swiss Singles Chart.
Jump up ^ "Nelly Furtado: Artist Chart History". Official Charts Company.
Jump up ^ "Nelly Furtado Chart History (Hot 100)". Billboard.
Jump up ^ "Nelly Furtado Chart History (Pop Songs)". Billboard.
Jump up ^ "Nelly Furtado Chart History (Adult Pop Songs)". Billboard.
Jump up ^ "Nelly Furtado Chart History (Adult Contemporary)". Billboard.
Jump up ^ "ARIA End Of Year Singles 2001 | Top 50 Australian Singles Chart". ARIA Charts. Australian Recording Industry Association. Retrieved December 12, 2017.
Jump up ^ "End of Year Charts 2001". Recorded Music NZ. Retrieved December 11, 2017.
Jump up ^ "Top 100 of 2001 - UK Music Charts". UK Charts. Retrieved December 12, 2017.
Jump up ^ "Billboard Top 100 - 2001". Retrieved 2010-09-29.
Jump up ^ "ARIA Charts – Accreditations – 2001 Singles". Australian Recording Industry Association. Retrieved July 9, 2015.
Jump up ^ "British single certifications – Nelly Furtado – I'm Like a Bird". British Phonographic Industry. Retrieved July 9, 2015. Enter I'm Like a Bird in the search field and then press Enter.
External links[edit]
"I'm Like a Bird" Official music video on YouTube
Lyrics of this song at MetroLyrics
Preceded by
"Bobcaygeon" by The Tragically Hip Juno Award for Best Single
2001 Succeeded by
"How You Remind Me" by Nickelback
[show]
v
t
e
Nelly Furtado
Awards and nominations
Discography
Studio albums
Whoa, Nelly!
Folklore
Loose
Mi Plan
The Spirit Indestructible
The Ride
Compilation albums
Mi Plan Remixes
The Best of Nelly Furtado
Live albums
Loose: The Concert
Concert tours
Burn in the Spotlight Tour
Come as You Are Tour
Get Loose Tour
Mi Plan Tour
The Spirit Indestructible Tour
Related topics
Mosley Music Group
[show]
v
t
e
Nelly Furtado songs
Discography
Whoa, Nelly!
"Hey, Man!"
"Shit on the Radio (Remember the Days)"
"I'm Like a Bird"
"Turn Off the Light"
Folklore
"Powerless (Say What You Want)"
"Explode"
"Try"
"Força"
"The Grass Is Green"
Loose
"Maneater"
"Promiscuous"
"No Hay Igual"
"Te Busqué"
"Say It Right"
"Do It"
"In God's Hands"
"All Good Things (Come to an End)"
Mi Plan
"Manos al Aire"
"Más"
"Bajo Otra Luz"
"Fuerte"
The Best of Nelly Furtado
"Night Is Young"
The Spirit Indestructible
"Spirit Indestructible"
"Big Hoops (Bigger the Better)"
"Parking Lot"
"Bucket List"
"Waiting for the Night"
The Ride
"Pipe Dreams"
Collaborations
"Get Ur Freak On"
"Ching Ching"
"Fotografía"
"Give It to Me"
"Sexy Movimiento (Remix)"
"Win or Lose"
"Broken Strings"
"Jump"
"Morning After Dark"
"Wavin' Flag"
"Who Wants to Be Alone"
"Hot-n-Fun"
"Is Anybody Out There?"
Retrieved from "https://en.wikipedia.org/w/index.php?title=I%27m_Like_a_Bird&oldid=815091273"
Categories:
2000 singles
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text:
Lost & Found Music Studios
From Wikipedia, the free encyclopedia
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This article needs additional citations for verification. Please help improve this article by adding citations to reliable sources. Unsourced material may be challenged and removed. (December 2016) (Learn how and when to remove this template message)
Lost & Found Music Studios
Genre
Teen drama
Docudrama
Musical
Created by
Frank Van Keeken
Starring
Shane Harte
Keara Graves
Deshaun Clarke
Ella Jonas Farlinger
Sarah Carmosino
Alex Zaichkowski
Levi Randall
Maranda Thomas
Alyssa Baker
Katrina Hachey
Olivia Solo
Rakim Kelly
Jeni Ross
Matthew Bacik
Michael Torontow
Ali Milner
Opening theme
"Lost and Found"
Country of origin
Canada
Original language(s)
English
No. of seasons
2
No. of episodes
27
Production
Executive producer(s)
Frank van Keeken
Ivan Schneeberg
David Fortier
Producer(s)
Laura Harbin
Jay Prychidny
Laurie McLarty
Camera setup
Multi-camera
Running time
23 minutes
Release
Original network
Family Channel, Netflix, CBBC
Picture format
480i (SDTV)
1080i (HDTV)
Original release
December 11, 2015 (2015-12-11) – present (present)
Chronology
Related shows
The Next Step
Lost & Found Music Studios is a Canadian musical-drama children's series created by Frank van Keeken and aired by Family Channel in Canada, CBBC in the United Kingdom and Ireland, and Netflix in all other territories globally. It is a music-centered spin-off of the dance-focused The Next Step, using a similar mockumentary format and sharing characters and locations; the main characters of Lost & Found initially appeared in The Next Step's third season. The series premiered December 11, 2015 on Family Channel;[1] its second season is available in Netflix territories and is currently airing in Canada and the UK.
Contents
[hide]
1 Synopsis
2 Cast
2.1 Main
2.2 Recurring
3 Episodes
3.1 Season 1 (2015-16)
3.2 Season 2 (2016-17)
4 References
5 External links
Synopsis[edit]
"A live music venue, recording studio and jam space, Lost & Found is an amazing place where young musicians go to become great. Members immerse themselves in music, write songs record tracks and form bands in hopes of turning their passion into a profession. But, if making it in the music industry wasn’t hard enough, these aspiring artists also have to deal with the many issues teens face including first crushes, peer pressure, difficult home lives and trying to fit in."[1]
Cast[edit]
Main[edit]
Shane Harte as Luke
Keara Graves as Leia
DeShaun Clarke as Jude
Ella Jonas Farlinger as Eva
Sarah Carmosino as Rachel
Alex Zaichkowski as John
Levi Randall as Theo
Trevor Tordjman as James
Maranda Thomas as Mary
Alyssa Baker as Maggie
Katrina Hachey as Hannah
Olivia Solo as Annabelle
Rakim Kelly as Isaac
Jeni Ross as Clara
Matthew Bacik as Nate
Michael Torontow as Mr. T
Ali Milner as Parker
Victoria Baldesarra as Michelle
Recurring[edit]
Brittany Raymond as Riley
Jordan Clark as Giselle
Lovell Adams-Gray as Tully
Kathryn Greco as Patricia
Lauren Thomas as Jackie
Bailey Pelkman as Britney
Ian Matthews as Thomas
Episodes[edit]
Season 1 (2015-16)[edit]
No. in season
Title
[show]Date of Release
1 Lost and Found December 11, 2015
2 See Through Me January 8, 2016
3 Play the Record January 15, 2016
4 Heart & Soul January 22, 2016
5 Invinicble January 29, 2016
6 All About the Music February 5, 2016
7 Day After Day February 12, 2016
8 Dancing in the Rain February 19, 2016
9 Potent Love February 26, 2016
10 Heart Shape March 4, 2016
11 Freebird March 11, 2016
12 Sunrise March 25, 2016
13 Callin' Callin' Part 1 April 1, 2016
14 Callin' Callin' Part 2 April 1, 2016
Season 2 (2016-17)[edit]
No. in season
Title
Date of Release
1 Sweet Tarts December 16, 2016
2 Rhythm In My Heatbeat January 13, 2017
3 Wondering January 20, 2017
4 Take Control January 27, 2017
5 Hit My Heart February 3, 2017
6 How Far We've Come February 10, 2017
7 Last Shot February 17, 2017
8 Take You There February 24, 2017
9 Let it Go March 3, 2017
10 Falling for You March 10, 2017
11 Call My Name March 17, 2017
12 You Could Have it All March 24, 2017
13 The Sound of Change March 31, 2017
References[edit]
^ Jump up to: a b http://www.dhxmedia.com/newsreleases/without-music-life-would-b-flat-lost-found-music-studios-debuts-january-8-on-family/
External links[edit]
Lost & Found Music Studios on IMDb
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